**3 Bulb Parallel Circuit**

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FiguRE 5–9 Current flow in a parallel circuit is analogous to water flow through a Ypipe. bulb 3. The current flowing through the light bulbs must return to the power source. Therefore, after the current flows through light bulb 3, it will combine at junction C with the current flowing through light bulb 2. The combined currents (from light bulbs 2 and 3) will combine at junction D with the current flowing through light bulb 1. The total recombined current will then flow through the conductor 2A — Figure 2. ln a series circuit, the same amount of current flows through the entire circuit. 8A 8 A— Figure 3. A simple parallel circuit. bulb that creates an additional ohm of resistance, the current will decrease to 3 amps. As a result.of the added resistance and decreased current, the bulb will lose about half of its brightness. This lack of brightness is also caused by the amount of voltage dropped by thebulb.ln the normal circuit.the bulb drops 12 volts. However, in the circuit with Magnetism and Electricity 3d Series and parallel circuits Relevant parts Of the POS: 4/1a how to design and construct series and parallel circuits 4/1b that the current in a series circuit depends on the number of Cells and the number and nature of other components and that current is not 'used up by components; 4/10 that energy is transferred from batteries to other Components Relevant Level Descriptions: Level 3 (bulb failing to light) Level 4 (connecting devices) Level 6 These.chapters also look into safety, design of production, testability, reliability, and thermal management of the designed circuit. This book is of great value to electrical and design engineers.So we can't just add up the resistance values to find total parallel circuit resistance—we need a new way of doing that. There are actually two ways. The first is the easiest if there are only two resistors in parallel. It can't calculate the resistance for more than two. Here it is, using R 1 = 6 ohms and R2 = 3 ohms as an example: R T = R1× R2 = 6 × 3 = 18 = 2, so RT = 2 ohms R1 + R2 = 6 + 3 =9 So the total resistance for a 6ohm resistor in parallel with a 3ohm resistor is 2 ohms.2 Disadvantage of a series circuit: (a) Damage to.any part of the circuit will stop the flow of current because there is only one path for current to flow through. (b) When more bulbs are added to the series circuit, the bulbs become dimmer because the electrical energy is shared by more bulbs. Parallel Circuit Ed 1 The current, voltage and resistance in parallel circuits are described as follows: (a) Current: • The current in the circuit is the sum of current flowing through each resistor, that is, First figure out the total resistance of the parallel circuit. We use a slightly different method here where we figure the total current flow through each leg of the parallel circuit if 12 volts is applied. Then we multiply this total by six, which is the number of bulbs. Once the total.current is figured, dividing it into the voltage gives us the total resistance. Each resistance draws 0.5 amps 1 2 volts/24 ohms = 0.5 amp 0.5 amp x 6 bulbs = 3 amps 1 2 volts/3 amps = 4 ohms Rt The resistance of the Answers may vary but should be either series or parallel. Parallel circuit: the brightness of the bulb will be the same as the original circuit. Series circuit: the bulb will be brighter. 3.b 4.d 7. Fuses, breakers 9. electrons 3. yes 4. yes 5. no 6. no Observation #2 1. Answers may vary but should be either series or parallel. 2. Parallel circuit: brightness of bulb will be the same. Series circuit: the bulb will be brighter. Conclusion: The bulb will be brighter when two batteries are in series than A 6volt battery.produces a current of 0.5 A. What is the power in the circuit? 2. 3 W A 100watt light bulb is operating on 1.2 A current. Whatis the voltage? 3. 83.3 W A potential difference of 120 V is operating on a 500wattmicrowave oven. What is the current being used? 4. 4.2 A Alightbulb uses 0.625A from a source of 120 V. How much power is used by the bulb? 5. 8. lightbulb Battery Name 52 lightbulb lightbulb Would series or parallel circuits be betterfor wiring light in a house?Use samesized bulbs. Take voltmeter readings and ammeter readings, and fill in the readings directly on the blank meter faces. We will discuss the results after you have them filled in. CURRENT FLOW IN A PARALLEL CIRCUIT Let us look at the ammeter reading first. Did you.notice Using Ohm's Law, let us figure the resistance: 12 volts 3 amps 1⁄4 4 ohms To continue the example, if we were to wire up an additional bulb of the same resistance, it would draw 3 amps of current also.